Anaconda Enterprise: Documentation

# 3.10. Examples

## 3.10.1. Matrix multiplication

Here is a naive implementation of matrix multiplication using a CUDA kernel:

    @cuda.jit
    def matmul(A, B, C):
        """Perform square matrix multiplication of C = A * B
        """
        i, j = cuda.grid(2)
        if i < C.shape[0] and j < C.shape[1]:
            tmp = 0.
            for k in range(A.shape[1]):
                tmp += A[i, k] * B[k, j]
            C[i, j] = tmp

This implementation is straightforward and intuitive but performs poorly, because the same matrix elements will be loaded multiple times from device memory, which is slow (some devices may have transparent data caches, but they may not be large enough to hold the entire inputs at once).

It will be faster if we use a blocked algorithm to reduce accesses to the device memory. CUDA provides a fast shared memory for threads in a block to cooperately compute on a task. The following implements a faster version of the square matrix multiplication using shared memory:

    from numba import cuda, float32

    # Controls threads per block and shared memory usage.
    # The computation will be done on blocks of TPBxTPB elements.
    TPB = 16

    @cuda.jit
    def fast_matmul(A, B, C):
        # Define an array in the shared memory
        # The size and type of the arrays must be known at compile time
        sA = cuda.shared.array(shape=(TPB, TPB), dtype=float32)
        sB = cuda.shared.array(shape=(TPB, TPB), dtype=float32)

        x, y = cuda.grid(2)

        tx = cuda.threadIdx.x
        ty = cuda.threadIdx.y
        bpg = cuda.gridDim.x    # blocks per grid

        if x >= C.shape[0] and y >= C.shape[1]:
            # Quit if (x, y) is outside of valid C boundary
            return

        # Each thread computes one element in the result matrix.
        # The dot product is chunked into dot products of TPB-long vectors.
        tmp = 0.
        for i in range(bpg):
            # Preload data into shared memory
            sA[tx, ty] = A[x, ty + i * TPB]
            sB[tx, ty] = B[tx + i * TPB, y]

            # Wait until all threads finish preloading
            cuda.syncthreads()

            # Computes partial product on the shared memory
            for j in range(TPB):
                tmp += sA[tx, j] * sB[j, ty]

            # Wait until all threads finish computing
            cuda.syncthreads()

        C[x, y] = tmp

Because the shared memory is a limited resources, the code preloads small block at a time from the input arrays. Then, it calls `syncthreads()` to wait until all threads have finished preloading and before doing the computation on the shared memory. It synchronizes again after the computation to ensure all threads have finished with the data in shared memory before overwriting it in the next loop iteration.